MOTOR armature current : Motor field strength?? The motor armeture a current = ((Vin - Vb)/Za) where Vin is the applied (terminal) voltage, Vb is the back EMF produced by the windings moving in the field from the field coils. Vb is proportional to The field strength and the speed of the motor. If the field current is reduced the current will increase (Due to lower Vb) increasing the speed until equalibrium is restored. Original Subject: Re: skin effect question With ro = radius of the round wire (meters) del = skin depth (meters) = 1/(pi*f*mu*sigma)^.5 f = frequency mu = material permeability (henrys/meter) (4*pi*10^-7 for good conductors) sigma = material conductivity (mhos/meter) (5.8*10^7 for copper, for example) Ro = 1/(pi*sigma*ro^2) (DC resistance) O ro/del < 2 (low frequencies) R/Ro = 1 + (1/48)*(ro/del)^4 (approx. 6 0.000000e+00rror at ro/del = 2) O ro/del > 2 (high frequencies) R/Ro = ro/(2*del) equation for current as: | Iz/Io | = e^[-(ro-r)/del] where r is distance measured from center of wire (So it looks to me that at 2*del from conductor edge, current has decreased to e^(-2) of its value at edge.)D3 Generator from motor 2 HP engine will not generate enough to supply 2500 watts. probably need 5 HP engine. assumes have efficient motor 2 HP power a hair dryer or TV. ======================MOTORS====================== Motors V N*delta_Phi/delta_time w*N*Phi*sin(wt) Torque K*I *sin(wt)